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2s^2-18s-104=0
a = 2; b = -18; c = -104;
Δ = b2-4ac
Δ = -182-4·2·(-104)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-34}{2*2}=\frac{-16}{4} =-4 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+34}{2*2}=\frac{52}{4} =13 $
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